Can any body give me some reference how to generate PN sequence with required
autocorrelation characteristics.If Pi is the sequence of length M

PiPj = M if i =j

PiPj = -1 else

Thank you

Rakesh

# Pn sequence generation

Started by ●May 5, 2009

Reply by ●May 6, 20092009-05-06

If M is a little number you can generate the first sequence evaluate

is energy and impose that this is M.

Then you can obtain the other sequence solving a linear system (rectangular) .

But what I do not know if the other sequence have energy equal to M.

E.G.

Suppose M=5

Generate 1^ sequence [A1 A2 A3 A4 A5]

Then

A1

B1 B2 B3 B4 B5 A2 -1

C1 C2 C3 C4 C5 x A3 = -1

D1 D2 D3 D4 D5 A4 -1

E1 E2 E3 E4 E5 A5 -1

To solve it use svd.

On 5/1/09, m...@yahoo.com wrote:

> Can any body give me some reference how to generate PN sequence with

> required autocorrelation characteristics.If Pi is the sequence of length M

> PiPj = M if i =j

> PiPj = -1 else

> Thank you

> Rakesh

>

is energy and impose that this is M.

Then you can obtain the other sequence solving a linear system (rectangular) .

But what I do not know if the other sequence have energy equal to M.

E.G.

Suppose M=5

Generate 1^ sequence [A1 A2 A3 A4 A5]

Then

A1

B1 B2 B3 B4 B5 A2 -1

C1 C2 C3 C4 C5 x A3 = -1

D1 D2 D3 D4 D5 A4 -1

E1 E2 E3 E4 E5 A5 -1

To solve it use svd.

On 5/1/09, m...@yahoo.com wrote:

> Can any body give me some reference how to generate PN sequence with

> required autocorrelation characteristics.If Pi is the sequence of length M

> PiPj = M if i =j

> PiPj = -1 else

> Thank you

> Rakesh

>

Reply by ●May 6, 20092009-05-06

Sorry yesterday I was confuse and the solution proposed in unfeasible.

On Tue, May 5, 2009 at 2:45 PM, arkkimede wrote:

> If M is a little number you can generate the first sequence evaluate

> is energy and impose that this is M.

>

> Then you can obtain the other sequence solving a linear system (rectangular) .

> But what I do not know if the other sequence have energy equal to M.

>

> E.G.

> Suppose M=5

>

> Generate 1^ sequence [A1 A2 A3 A4 A5]

>

> Then

> A1

> B1 B2 B3 B4 B5 A2 -1

> C1 C2 C3 C4 C5 x A3 = -1

> D1 D2 D3 D4 D5 A4 -1

> E1 E2 E3 E4 E5 A5 -1

>

> To solve it use svd.

> On 5/1/09, m...@yahoo.com wrote:

>> Can any body give me some reference how to generate PN sequence with

>> required autocorrelation characteristics.If Pi is the sequence of length M

>> PiPj = M if i =j

>> PiPj = -1 else

>> Thank you

>> Rakesh

>

On Tue, May 5, 2009 at 2:45 PM, arkkimede wrote:

> If M is a little number you can generate the first sequence evaluate

> is energy and impose that this is M.

>

> Then you can obtain the other sequence solving a linear system (rectangular) .

> But what I do not know if the other sequence have energy equal to M.

>

> E.G.

> Suppose M=5

>

> Generate 1^ sequence [A1 A2 A3 A4 A5]

>

> Then

> A1

> B1 B2 B3 B4 B5 A2 -1

> C1 C2 C3 C4 C5 x A3 = -1

> D1 D2 D3 D4 D5 A4 -1

> E1 E2 E3 E4 E5 A5 -1

>

> To solve it use svd.

> On 5/1/09, m...@yahoo.com wrote:

>> Can any body give me some reference how to generate PN sequence with

>> required autocorrelation characteristics.If Pi is the sequence of length M

>> PiPj = M if i =j

>> PiPj = -1 else

>> Thank you

>> Rakesh

>